13 million kilometers would be about one-quarter of the distance between Mercury and the Sun, so I am inclined to go with 1 as well. Although that’s about 95 Jupiter diameters out from the planet. Being the 22nd orbit, I guess it makes sense…?
Presuming that Godrippe is the satellite of a gas giant, since orbit Dub represents a multiplier of 600, that would make its gas giant’s mean diameter 13,354,800 km ÷ 600 km ⁄ mi = 22,258 mi = 35,820.778752 km, around 72.74% of Neptune’s mean diameter.
Kepler’s third law can be used to determine the mass of Godrippe’s gas giant:
M = 4π² ×
a³ ÷
GT², where
a is the semi-major axis of the orbit in meters,
G is the gravitational constant, and
T is the orbital period in seconds. Thus,
M = 39.4784176… × (13,354,800,000 m)³ ÷ (6.6743×10⁻¹¹ m³ ⁄ (s² kg) × (197,665,862.5744608 s)²) ≅ 3.60581×10²⁵ kg
Since the gas giant’s volume
V = (π ⁄ 6) × (35,820,778.752 m)³ ≅ 2.40659878×10²² m³, the gas giant’s mean density
ρ =
M ⁄
V ≅ 1,498.3 kg ⁄ m³, around 91.48% of Neptune’s mean density.
These results are plausible, so the explanation of why Godrippe’s upper temperature limit is 1,060 °C — only a few kelvins shy of the melting point of gold — must be due to the details regarding the gas giant’s orbit around their star.